Probability of One Adult Winner in Random Lucky Draw: Homework Solution

  • Thread starter Thread starter icystrike
  • Start date Start date
  • Tags Tags
    Probability
Click For Summary

Homework Help Overview

The problem involves calculating the probability of selecting one adult winner in a random lucky draw from a group consisting of men, women, and children. The participants include 15 men, 10 women, and a total of 8 children, with the exact breakdown of the children being unclear.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial approach to the problem, questioning the total number of participants and the classification of children. There is an exploration of the probabilities associated with selecting adults versus children.

Discussion Status

The discussion is ongoing, with participants raising questions about the assumptions made regarding the number of children and the total count of participants. Some guidance has been offered regarding the calculation of probabilities, but no consensus has been reached on the correct interpretation of the problem.

Contextual Notes

There is ambiguity regarding the number of children, as the phrasing in the problem statement is noted to be potentially misleading. This has led to confusion about the total number of participants and the classification of adults versus children.

icystrike
Messages
444
Reaction score
1

Homework Statement


The question goes like this:
15 men , 10 ladies , 8 girls and boys took part in a lucky draw , A winner was picked at random, after which another winner was picked from the remaining people.

Find the probability that among the two winners , only one of the is an adult.

I understand already! thanks for the PM



Homework Equations





The Attempt at a Solution


I was trying to let An be the nth adult and Cn be the nth Children

and my answer is A1C2+C1C2 or C1A2+C1C2
whereby my answer will be 25/40*15/39+15/40*15/39 or 15/40*25/39+15/40*15/39
however i am wrong..
 
Last edited:
Physics news on Phys.org


You seem to be under the false impression that there are 40 people here
 
Are there 8 girls and 8 boys = 16 kids or 8 kids, both girls and boys?
 


futurebird said:
Are there 8 girls and 8 boys = 16 kids or 8 kids, both girls and boys?
The problem said " 8 girls and boys", NOT "8 girls and 8 boys". There are 25 adults and 8 "non" adults. (Even if you assumed 8 girls and 8 boys, that would be a total of 25+ 16= 41, not 40.)

You say in your first post, "my answer is A1C2+C1C2 or C1A2+C1C2
whereby my answer will be 25/40*15/39+15/40*15/39 or 15/40*25/39+15/40*15/39
however i am wrong.."

Without giving any idea HOW you got that answer.

What is the probability that the first person chosen is NOT an adult? Given that, what is the probability that the second person chosen IS an adult?

What is the probability that the first person chosen IS an adult? Given that, what is the probability that the second person chosen is NOT an adult?

So what is the probability that exactly one of the people chosen is an adult?
 

Similar threads

Replies
1
Views
2K
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 11 ·
Replies
11
Views
6K
Replies
147
Views
10K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K