Probability of the Union of Indepedent Events

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SUMMARY

The probability of the union of independent events A1, A2, ..., An is expressed as P(A1 U A2 U ... An) = 1 - [1-P(A1)][1-P(A2)]...[1-P(An)]. This formula derives from the principle that for independent events, the probability of their intersection is the product of their individual probabilities, P(A)P(B). The discussion highlights the challenge of extending the proof from the case of two events to n events, emphasizing the application of De Morgan's Law for n events to facilitate the proof.

PREREQUISITES
  • Understanding of probability theory, specifically independent events
  • Familiarity with De Morgan's Laws in set theory
  • Basic algebraic manipulation skills
  • Knowledge of probability notation and terminology
NEXT STEPS
  • Study the proof of the union of two independent events in detail
  • Research De Morgan's Laws and their applications in probability
  • Explore combinatorial proofs related to independent events
  • Learn about the inclusion-exclusion principle in probability
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Students studying probability theory, mathematicians interested in combinatorial proofs, and educators teaching concepts of independent events and their probabilities.

Obraz35
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Homework Statement


Show that if A1, A2, ..., An are independent events then
P(A1 U A2 U ... An) = 1 - [1-P(A1)][1-P(A2)]...[1-P(An)]


Homework Equations


If A and B are independent then the probability of their intersection is P(A)P(B).
The same can also be said of AC and B.

The Attempt at a Solution


I have managed to prove this algebraically for the case where n=2. But I am having trouble trying to do it for the general case since it is not as easy to break down the union of A1 through An into a union of disjoint sets as it was for n=2.
 
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Apply De Morgan's Law (for n events)
 

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