1. The problem statement, all variables and given/known data I made this question for myself to try to see if I could use two approaches (Poisson Distribution and Binomial Distribution) to solve a problem: Someone's average is to make 1 out of every 3 basketball shots. What are the chances she makes exactly 2 shots in a trial of 3 attempts? 2. Relevant equations Poisson Distribution: (λ^k)(e^-λ)/(k!) Binomial Distribution: (n choose k)(P^k)((1-P)^(n-k)) 3. The attempt at a solution Poisson approach: λ is the average of successes in a given series length = 1 k is the queried amount of successes in the same series length = 2 Answer = (1^2)(e^-1)/(2!) = .184 Binomial approach: n is the number of attempts = 3 k is the number of queried successes = 2 P is the probability of success = (1/3) Answer = (3 choose 2) (1/3)^2 (2/3)^1 = .222 I have a feeling using Poisson here is wrong but I am not sure why. I have seen this type of problem used as an example for use of both Poisson and Binomial distributions. Thanks.