Probability Problems: P(X≤15)=0.3, P(15<X≤24)=0.6, P(X>20)=0.5

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The discussion centers around a probability problem where the initial values provided were incorrect, particularly with one probability stated as 6, which is impossible. Participants clarify that the correct probabilities should be P(X≤15)=0.3, P(15<X≤24)=0.6, and P(X>20)=0.5. The main question is to find P(15<X≤20), which is determined to be 0.2. The thread highlights the importance of accurate problem formulation in probability discussions.
Mesmer
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Let P(X\leq \15)= 0.3, P(15\less X \leq24)=6 and (P X > 20) = 0.5I don't understand how I would find this probability: P(15\lessX\leq20

The answer is 0.2.
 
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Are you sure you posted the problem correctly? The probability of an event cannot equal 6, first of all.
 
You are correct, the problem is not posted correctly. My latex coding is lacking...I wish there were a way a could delete this post.
 
Is it meant to be 0.6 by any chance? Thus, is your first equation meant to be P(X\leq \15)= 0.3,\ \ P(15&lt; X \leq24)=0.6,\ \ P(X&gt;20)=0.5, and you want to find P(15&lt; X \leq20)?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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