Probability question - Binomial distribution

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SUMMARY

The discussion focuses on calculating the probability of obtaining two heads when tossing two unbiased coins repeatedly until achieving this outcome. The random variable X represents the number of throws required, with the expression for P(X=r) initially proposed as P(X=r)=nCr (1/4)^r (3/4)^(n-r). However, participants clarify that the number of trials can be infinite, leading to a zero probability for certain outcomes. The problem is ultimately related to infinite geometric series, emphasizing the need for a proper understanding of the binomial distribution and its application in this context.

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Homework Statement



A game is played by tossing two unbiased coins repeatedly until two heads are obtained in the same throw. The random variable X denotes the number of throws required. Find the expression for P(X=r).

Homework Equations





The Attempt at a Solution



It looks to be a binomial distribution but the number of trials could be infinity. I have no idea to class this into which distribution(so far i have learned binomial, poisson and normal).

The best i can get is

P(X=r)=nCr (1/4)^r (3/4)^(n-r)
 
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What is n supposed to be?

The number if trials could be infinite, but the probability of that happening is zero. The setup is similar to if someone just flipped one coin until they got a heads; do you know how to solve that problem?
 


Office_Shredder said:
What is n supposed to be?

The number if trials could be infinite, but the probability of that happening is zero. The setup is similar to if someone just flipped one coin until they got a heads; do you know how to solve that problem?

It's an infinite geometric series probability(not sure what to call that).

1/2 + (1/2)^2 + (1/2)^3 + (1/2)^4 + ...

but now two coins are flipped together, i am not sure how to do that here.
 

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