1. The problem statement, all variables and given/known data A body standing on a bridge throws a stone vertically upwards with a velocity of 20 m/s. it strikes the water below after 3 seconds, the height of the bridge over the water level in the river is : a. 45 m b. 10 m c. 5 m d. 15 m 2. Relevant equations vf^2= 2aS + vi^2 3. The attempt at a solution its ans mentioned in key is 5m, but i dnt undrstand how !! The time taken to reach max height (h) is given by.. v = u - gt .. where v = 0 m/s t = u/g .. .. 20m/s / 9.80m/s² = 2s .. So it takes 2x2s (4s) to return to the position it was thrown from (on the bridge) .. yet the question gives a time 3s to reach the water below the bridge.