Problem in solving question related to acceleration and velocity

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SUMMARY

The discussion centers on a physics problem involving a lift moving upwards with an acceleration of 2 m/s² and a stone dropped from it when the lift's velocity is 8 m/s. The key equations utilized include a = (v - u) / t and d = avg v * t. Participants agree that the stone does not fall the full 3 meters due to the lift's upward acceleration, prompting a deeper analysis of the relative velocity and acceleration of the stone and the lift system.

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Homework Statement


s lift whose cage in 3 m high is moving up with an acceleration of 2m/s^2. A piece of stone in dropped for the top of the cage of the lift when its velocity is 8 m/s, if g = 10 m/s^2, then the stone will reach the floor of the lift after how many seconds?

Homework Equations



a = (v - u) / t
d = avg v * t

The Attempt at a Solution


I tried to think that if the lift is moving upwards, then when the stone will be dropped it won't have to fall full 3 m because the lift is also moving up so i think we have to add the velocity 8m/s and the velocity with which the stone is moving.
 
Last edited:
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My interpretation.
http://img515.imageshack.us/img515/3747/p1010019qd.jpg
 
Last edited by a moderator:
You were right to think that the stone won't have to fall the full 3 meters, since the lift is accelerating upwards. But I'm not sure if that is the easiest way to think about it. Ask yourself: what is the cage/stone system's relative velocity and acceleration?
 

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