1. The problem statement, all variables and given/known data s lift whose cage in 3 m high is moving up with an acceleration of 2m/s^2. A piece of stone in dropped for the top of the cage of the lift when its velocity is 8 m/s, if g = 10 m/s^2, then the stone will reach the floor of the lift after how many seconds? 2. Relevant equations a = (v - u) / t d = avg v * t 3. The attempt at a solution I tried to think that if the lift is moving upwards, then when the stone will be dropped it won't have to fall full 3 m because the lift is also moving up so i think we have to add the velocity 8m/s and the velocity with which the stone is moving.