Problem involving Probability density function

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The discussion centers on the correctness of an inequality in a probability density function (pdf) context, specifically regarding the equivalence of "< 0.5" and "≤ 0.5" in continuous distributions due to the zero measure of the point 0.5. Participants confirm that evaluating the pdf at 0.5 is equivalent to finding the cumulative distribution function (cdf) at that point, resulting in F(0.5)=0.125. There is a debate about whether the expression should involve the integral of f(x) instead of x, with one participant suggesting it may be a typo. The conversation highlights the nuances of interpreting probability functions in statistical literature. Overall, the discussion emphasizes the importance of precision in mathematical expressions related to probability.
chwala
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Homework Statement
see attached
Relevant Equations
stats
1648817667989.png


I just want to be certain, i think the inequality indicated is not correct...ought to be less than. Kindly confirm...This is a textbook literature.
 
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In terms of continuous probability distributions ##< 0.5## and ##\le 0.5## are equivalent, because the point ##0.5## itself has zero width (or zero measure if you prefer).
 
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PeroK said:
In terms of continuous probability distributions ##< 0.5## and ##\le 0.5## are equivalent, because the point ##0.5## itself has zero width (or zero measure if you prefer).
Thanks Perok, so the pdf indicated above is just the same as finding the cdf at ##x=0.5## right? giving us ##F(0.5)=0.125##.
 
chwala said:
Thanks Perok, so the pdf indicated above is just the same as finding the cdf at ##x=0.5## right? giving us ##F(0.5)=0.125##.
I think so. I haven't looked very carefully at the material you posted.
 
1648818911263.png


ought to be integral of ##f(x)## and not ##x##... or is it fine the way it is?
 
chwala said:
View attachment 299242

ought to be integral of ##f(x)## and not ##x##... or is it fine the way it is?
Isn't it obvious that's a typo?
 
ok cheers Perok.
 

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