Problem involving Probability density function

chwala
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Homework Statement
see attached
Relevant Equations
stats
1648817667989.png


I just want to be certain, i think the inequality indicated is not correct...ought to be less than. Kindly confirm...This is a textbook literature.
 
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In terms of continuous probability distributions ##< 0.5## and ##\le 0.5## are equivalent, because the point ##0.5## itself has zero width (or zero measure if you prefer).
 
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PeroK said:
In terms of continuous probability distributions ##< 0.5## and ##\le 0.5## are equivalent, because the point ##0.5## itself has zero width (or zero measure if you prefer).
Thanks Perok, so the pdf indicated above is just the same as finding the cdf at ##x=0.5## right? giving us ##F(0.5)=0.125##.
 
chwala said:
Thanks Perok, so the pdf indicated above is just the same as finding the cdf at ##x=0.5## right? giving us ##F(0.5)=0.125##.
I think so. I haven't looked very carefully at the material you posted.
 
1648818911263.png


ought to be integral of ##f(x)## and not ##x##... or is it fine the way it is?
 
chwala said:
View attachment 299242

ought to be integral of ##f(x)## and not ##x##... or is it fine the way it is?
Isn't it obvious that's a typo?
 
ok cheers Perok.
 
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