Problem involving temp changes in stress and strain topic.

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SUMMARY

This discussion focuses on determining the temperature at which the normal stress in an aluminum bar equals -90 MPa, given a 0.5 mm gap at 20 degrees Celsius. The solution involves understanding thermal expansion, specifically the coefficient of linear expansion (alpha), and how it affects the length of the aluminum bar under varying temperatures. Participants express a need for guidance on the calculations involved in thermal stress and strain relationships.

PREREQUISITES
  • Understanding of thermal expansion and the coefficient of linear expansion (alpha).
  • Knowledge of stress-strain relationships in materials, particularly in metals.
  • Familiarity with basic mechanics of materials, including axial loading effects.
  • Ability to perform calculations involving temperature changes and material properties.
NEXT STEPS
  • Research the coefficient of linear expansion for aluminum and its implications in thermal stress calculations.
  • Learn about the relationship between temperature changes and stress in materials using the formula for thermal stress.
  • Study the mechanics of materials, focusing on axial loads and their effects on length changes in bars.
  • Explore case studies or examples involving temperature-induced stress in metals to solidify understanding.
USEFUL FOR

Mechanical engineers, materials scientists, and students studying thermodynamics and material mechanics will benefit from this discussion, particularly those interested in thermal stress analysis in metals.

Nicolesin
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1. Knowing that a 0.5 mm gap exists when the temperature is 20 degree celsius,
Determine the tempature at which the normal stress in the aluminum bar will be equal to -90 MPa,And the corresponding exact length of the aluminum bar.

The Attempt at a Solution


I am not familiar with this topic. Could anyone also show me some of their thing process . Thanks in advance.
 
Physics news on Phys.org
Do you know how much expansion occurs in metals with temperature change?
Hint: it involves alpha.

Do you know how the length of a bar changes when an axial load is applied?
 

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