Optics Problem: Find Smallest Refractive Index of Slab

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To determine the smallest refractive index of a rectangular slab that allows all incident light to emerge from the opposite face, total internal reflection must occur at specific angles. The critical angle, denoted as θ_c, is essential in this scenario, leading to the condition that the angle of incidence must exceed θ_c for total internal reflection. The relationship between the angle of refraction and the refractive index indicates that n must be greater than sec(r), where r is the angle of incidence. The discussion emphasizes re-evaluating the maximum angle r in terms of arc-sin functions to derive a valid refractive index. Ultimately, the solution reveals that the refractive index cannot be infinite, prompting a more precise calculation to find the correct value.
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Homework Statement


Light falls on the surface AB of a rectangular slab from air. Determine the smallest refractive index n that the material of the slab can have so that all incident light emerges from the opposite face CD.
upload_2015-6-9_20-39-0.png


Homework Equations

The Attempt at a Solution


Let's think about this case:
upload_2015-6-9_20-49-45.png

There must be total internal reflection at Q and S.
That means, ##90-r>\theta _c## [##\theta _c## is the critical angle]
## sin(90-r)>sin \theta _c##
##cos r > \frac{1}{n}## [## sin \theta _c = \frac {1}{n}##]
##n>sec(r)##
But, the maximum value of ##sec(r)## is infinite.
That means n should be infinite.
But that is not the answer.
 
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Try it again. Write down the maximum ##r## in terms of arc-sin of something. Write down ##\theta_C## in terms of arc-sin of something. Then write down ##90-r > \theta_C## in terms of these arc-sin formulas. Don't forget that air has an index of refraction very close to 1. See what you get.
 
I have got the answer. :)
 
..
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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