Problem with heat capacity of thermal system

Click For Summary
The discussion revolves around a thermal equilibrium problem involving water, silver, and an unknown substance. In part (a), the equilibrium temperature after adding 100g of silver to 200g of water is calculated to be 28°C. In part (b), participants express confusion about how to set up the heat transfer equations after adding 100g of an unknown substance, which raises the temperature by an additional 26°C. The correct approach involves calculating the heat gained by the water and silver at 28°C and the heat lost by the unknown substance cooling from 300°C. The final conclusion suggests that the specific heat capacity of the unknown substance is determined to be approximately 908.9 J/kg/K, although there is debate about the validity of identifying it as oxygen.
Pouyan
Messages
103
Reaction score
8

Homework Statement


a) a styrofoam cup contains 200g of water at 20 C.What will be the equilibrium temp of the system after 100g of silver,initially at 300 C,has been added?you may assume that the heat capacity of the cup is negligible and that no heat is lost to the surroundings.

(b) a further 100g of an unknown substance,also at 300 C is now added to the system and the temperature rises by a further 26 degrees celsius
what is the specific heat capacity of the unknown substance?(the specific heat of water is 4180 Jkg^-1 K^-1 and that of silver 240 J kg^-1 K^-1)

Homework Equations


a) Q before = Q after
Q before = Mass of water * C water * (T - 20)
Q after = Mass of silver * C silver * (300-T)

b) My problem is this part. I don't know how I can set up the equation when a new substance is added to this system. Would please someone help me with part b of this question?!

The Attempt at a Solution


a) T = 28 C
 
Physics news on Phys.org
Pouyan said:

Homework Statement


a) a styrofoam cup contains 200g of water at 20 C.What will be the equilibrium temp of the system after 100g of silver,initially at 300 C,has been added?you may assume that the heat capacity of the cup is negligible and that no heat is lost to the surroundings.

(b) a further 100g of an unknown substance,also at 300 C is now added to the system and the temperature rises by a further 26 degrees celsius
what is the specific heat capacity of the unknown substance?(the specific heat of water is 4180 Jkg^-1 K^-1 and that of silver 240 J kg^-1 K^-1)

Homework Equations


a) Q before = Q after
Q before = Mass of water * C water * (T - 20)
Q after = Mass of silver * C silver * (300-T)

b) My problem is this part. I don't know how I can set up the equation when a new substance is added to this system. Would please someone help me with part b of this question?!

The Attempt at a Solution


a) T = 28 C
After the 200 g of water and the 100 g of silver in Part a) have reached thermal equilibrium, both are at the same temperature.

In Part b), you start with the equilibrium temperature from Part a) with the water and silver, but now you have added 100 g of an unknown material which raises the temperature of the water and silver by 26° C while the unknown substance is cooled from 300° C. This requires no special setup, just regular bookkeeping of the amount of heat added to the water and silver and the amount of heat lost by the mystery material.
 
  • Like
Likes Pouyan
SteamKing said:
After the 200 g of water and the 100 g of silver in Part a) have reached thermal equilibrium, both are at the same temperature.

In Part b), you start with the equilibrium temperature from Part a) with the water and silver, but now you have added 100 g of an unknown material which raises the temperature of the water and silver by 26° C while the unknown substance is cooled from 300° C. This requires no special setup, just regular bookkeeping of the amount of heat added to the water and silver and the amount of heat lost by the mystery material.
Thanks but I think so :

in this case :

Q before : (mass of water*Cw + mass of silver*Cs) * (28 + 26)
Q after : (mass of x * Cx )(300-26)

when I try to eject Cx from Q before= Q after, I get wrong value
The correct answer is Oxygen (908.9 J/kg/K)

What is wrong with this equation?!
 
Pouyan said:
Thanks but I think so :

in this case :

Q before : (mass of water*Cw + mass of silver*Cs) * (28 + 26)

The water and silver are already at a temperature of 28° C, before the unknown substance is added. The heat transfer from this unknown substance is going to raise the temperature of the water and silver by 26° C, not by (28° + 26°).
Q after : (mass of x * Cx )(300-26)

when I try to eject Cx from Q before= Q after, I get wrong value
The correct answer is Oxygen (908.9 J/kg/K)

What is wrong with this equation?!

It's not clear how you determined the unknown substance was Oxygen, which, as far as I know, is a gas at a temperature of 300° C
 
SteamKing said:
The water and silver are already at a temperature of 28° C, before the unknown substance is added. The heat transfer from this unknown substance is going to raise the temperature of the water and silver by 26° C, not by (28° + 26°).

It's not clear how you determined the unknown substance was Oxygen, which, as far as I know, is a gas at a temperature of 300° C

I get 1887 which is not the correct answer... I don't know how I can solve it
 
Pouyan said:
I get 1887 which is not the correct answer... I don't know how I can solve it
I have no idea what 1887 means, what units it has, or how you got it.

Please post your calculations.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
21
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K