- #1
SanEng02
- 5
- 0
I was doing a problem that required me to initially find the amount of pressure that was acting on a bubble, I decided that I had to use the equation P=P(STP) + ρgd. But looking at the equation, the units for the ρgd part of the problem doesn't make sense about how that gives me a unit of pressure (Pascal).2. So I worked it out and:
ρ= kg/m^3
g= m/s^2
d= m
when multiplied together your units become kg/ms^2 which you are then adding to a pascal unit. So my question really is, is 1 kg/ms^2 = 1 Pa?
An explanation would be much appreciated!
ρ= kg/m^3
g= m/s^2
d= m
when multiplied together your units become kg/ms^2 which you are then adding to a pascal unit. So my question really is, is 1 kg/ms^2 = 1 Pa?
An explanation would be much appreciated!