I have a problem with the calculus of magnetic moment of Li-6.(adsbygoogle = window.adsbygoogle || []).push({});

The configuration of protons is [itex]1p_{3/2}[/itex], and the neutrons' one is the same.

I have to add the magnetic moment of uncoupled proton and uncoupled neutron.

I use the following formula for [itex]J=l+\frac{1}{2}[/itex] (J is the particle spin):

[itex]\frac{\mu}{\mu_N}=g_lJ+\frac{g_s-g_l}{2}[/itex]

For the proton I have: [itex]g_l=1; g_s=5.58 \rightarrow \frac{\mu}{\mu_N}=J+2.29=3.79[/itex]

For the neutron I have: [itex]g_l=0; g_s=-3.82 \rightarrow \frac{\mu}{\mu_N}=-1.91[/itex]

So the total [itex]\frac{\mu}{\mu_N}=3.79-1.91=1.88[/itex], exactly 1 more than the correct value, 0.88!

What's wrong?

**Physics Forums - The Fusion of Science and Community**

# Problem with shell model and magnetic moment of Lithium-6

Have something to add?

- Similar discussions for: Problem with shell model and magnetic moment of Lithium-6

Loading...

**Physics Forums - The Fusion of Science and Community**