- #1

BOAS

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## Homework Statement

I am trying to calculate the nuclear magnetic moment for Oxygen 15 but my answer differs strongly from the value quoted in literature.

## Homework Equations

## The Attempt at a Solution

[/B]

##\mu_J = g_J \mu_N J##

This isotope of Oxygen has an unpaired Neutron with ##J = \frac{1}{2}##.

Calculating the nuclear g-factor for ##J = l + \frac{1}{2}##

##g_J = g_l (1 - \frac{1}{2J}) + g_s(\frac{1}{2J})##

For a neutron ##g_l = 0## and so in this case ##g_J = g_s = -3.82##

I therefore find that ##\mu_J = -1.91 \mu_N## which is significantly different from the value I find in the NIST table of ##\pm 0.7189 \mu_N##

http://nist.gov/data/PDFfiles/jpcrd85.pdf

Is my treatment too simplistic to get a decent prediction, or am I making a fundamental error?

Thanks for reading!