- #1
BOAS
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Homework Statement
I am trying to calculate the nuclear magnetic moment for Oxygen 15 but my answer differs strongly from the value quoted in literature.
Homework Equations
The Attempt at a Solution
[/B]
##\mu_J = g_J \mu_N J##
This isotope of Oxygen has an unpaired Neutron with ##J = \frac{1}{2}##.
Calculating the nuclear g-factor for ##J = l + \frac{1}{2}##
##g_J = g_l (1 - \frac{1}{2J}) + g_s(\frac{1}{2J})##
For a neutron ##g_l = 0## and so in this case ##g_J = g_s = -3.82##
I therefore find that ##\mu_J = -1.91 \mu_N## which is significantly different from the value I find in the NIST table of ##\pm 0.7189 \mu_N##
http://nist.gov/data/PDFfiles/jpcrd85.pdf
Is my treatment too simplistic to get a decent prediction, or am I making a fundamental error?
Thanks for reading!