Problem With Work Done by a Spring Force

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Homework Help Overview

The problem involves a spring-block system where a force is applied to hold the block stationary at a specific position. The task is to determine the block's position after a certain amount of work has been done on the system, with the spring's properties being central to the discussion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the spring constant and the final position of the block using work-energy principles. Some participants question the calculations and suggest that there may be issues with significant digits affecting the acceptance of the answer.

Discussion Status

The discussion includes attempts to verify the calculations and explore potential issues with the answer format. Participants express uncertainty about the correctness of the original poster's work and consider the implications of significant digits on the final answer.

Contextual Notes

The problem is constrained by the requirement to adhere to significant digits based on the provided values, which are given to 1 or 2 significant digits.

Senrai
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Homework Statement


One end of a spring is attached to a block and the other is attached to a wall. The spring has no mass and the block lies atop a frictionless surface. The equilibrium point of the system is at x = 0 cm. A force of 80N must be applied to the block to hold it stationary at x = -2 cm. From this position, the block is slowly moved until the applied force has done 4J of work on the spring-block system; the block is then again stationary. What is the block's position? (There are two answers.)

Homework Equations


-Fspring = Fapplied
Fspring = -kx
-Wspring = Fapplied
Wspring = 0.5k(x12 - x22)

The Attempt at a Solution


I first solved to get the spring's spring constant, k.
-Fspring = Fapplied
-Fspring = 80N
Fspring = -80N

Fspring = -kx
-80N = -k(-0.02m)
-80N/-(-0.02m) = k
-4000N/m = k
I don't think there can be negative spring constants, so I changed this to 4000N/m.

I then solved to get the block's final position.
-Wspring = Fapplied
-Wspring = 4J
Wspring = -4J

Wspring = 0.5k(x12 - x22)
-4J = 0.5(4000N/m)((-0.02m)2 - x22)

When I worked that equation out, I came up with a final position of +- 0.04899m, which was incorrect.
I've been at this for hours and can't solve it. Any help would be greatly appreciated.
 
Last edited:
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Senrai,

I don't see anything wrong with your work. Maybe someone else can see something that I don't.
 
I got this answer as well.
 
heth said:
I got this answer as well.

Though there may be an issue with the number of significant digits in your answer. 4 SD for your answer is a lot for a problem where all the values and given to 1 or 2 SD.

I don't know if you have some kind of automated answer system or how they're programmed, but it could be rejecting the answer because of this.
 
Thanks all. It must have been a problem with the program I was inputting the answer into. I did round off to the proper amount of significant digits when inputting the final answer into the program. After several more tries of doing the problem exactly like that, it's finally accepted the answer as correct. Thanks for your help.
 

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