1. The problem statement, all variables and given/known data A block with mass 2.90kg is attached as shown to a spring with a force constant of 492.0N/m. The coefficient of kinetic friction between the block and the surface on which it slides is 0.170. The block is pulled 5.30cm to the right of its equilibrium position and then released from rest. What is the speed of the block as it passes by its equilibrium position? Rough image: /\/\/\/\/\/\/\/|B_L_O_C_K| 2. Relevant equations PEspring=1/2kx^2 Fspring=kx Ffriction=(mu)*Force Normal Work=F*d 3. The attempt at a solution First, I found the force of Friction by multiplying the coefficient of friction by the force normal of the block due to gravity ("ma=mg=2.9*9.81=28.449N). Then, I attempted to use W=F*d to find the work done by friction. I then decided to try finding Wspring=F*d=kx*d (Where "d"=x, thus it would be "x^2"), and from there assumed that the Wnet=Wspring-Wfriction. However, that doesn't appear to be the proper method. In particular, if someone could explain the relationship of Work to Kinetic Energy AS WELL AS Potential Energy, that would be very helpful.