Product moment of inertia of an inclined section of a beam

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SUMMARY

The discussion focuses on deriving the product moment of inertia (Ixy) for an inclined section of a beam using integration techniques. The correct formula for Ixy is established as Ixy = L³t(sin²θ)/24. Participants clarify the necessary parameters, including the orientation of the rod in the x-y plane and the definition of thickness (t). The integration limits for the variable s are specified as L/2 and -L/2, which are crucial for accurate calculations.

PREREQUISITES
  • Understanding of product moment of inertia in structural engineering
  • Familiarity with integration techniques in calculus
  • Knowledge of coordinate transformations, specifically for inclined sections
  • Basic concepts of beam theory and moment of area
NEXT STEPS
  • Study the derivation of Ixx and Iyy for various beam orientations
  • Learn about coordinate transformations in structural analysis
  • Explore advanced integration techniques for calculating moments of inertia
  • Investigate applications of product moment of inertia in beam design
USEFUL FOR

Structural engineers, civil engineering students, and anyone involved in beam analysis and design will benefit from this discussion.

emRage
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Hi guys,

I would like to derive the Ixy equation from simple integration and I can't seem to get the right answer (third equation down the picture). I seem to be able to derive Ixx and Iyy easily but product moment of area requires first moment of area to be calculated and I just don't know how to do that on an inclined section.

Any help would be apprecited on this issue.

Thank you.
 

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Welcome to PF!

Hi emRage! Welcome to PF! :wink:

Is the rod in the x-y plane? And what is t?

ok, you need to prove that Ixy = L3t(sin2θ)/24.

Show us the integral you have for this. :smile:
 
This one I've figured out! :-p

x = cos(theta) . s
y = sin(theta) . s
dA = ds . thickness
limits for s = L/2 and -L/2

Thanks anyway!
 

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