Product Permutations/cycle notation

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SUMMARY

The discussion focuses on computing the product permutation qp = (1452) * (341)(25) using cycle notation. The correct result is identified as (135), where qp sends 1 to 3, 3 to 5, and 5 to 1. The process involves applying the rightmost permutation first and then determining the subsequent mappings through the cycles. Key insights include understanding how each cycle interacts with the elements and the importance of following the order of operations in permutations.

PREREQUISITES
  • Understanding of cycle notation in permutations
  • Familiarity with the concept of product permutations
  • Knowledge of how to apply permutations from right to left
  • Basic skills in abstract algebra, particularly group theory
NEXT STEPS
  • Study the properties of symmetric groups and their permutations
  • Learn about the composition of permutations in detail
  • Explore cycle decomposition and its applications
  • Practice additional examples of product permutations and their computations
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Students studying abstract algebra, particularly those focusing on permutations and group theory, as well as educators looking for examples to illustrate product permutations.

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Homework Statement



This is just an example in a textbook but I'm completely stumped.
This is dealing with cycles, and product permutations.
So we have
p=(341)(52)
q = (1452)

and we want to compute the product permutation qp

Homework Equations



so qp = (1452) * (341)(25)

The book writes p sends 3 to 4 and q sends 4 to 5 so qp sends 3 to 5.

The Attempt at a Solution



I know that we proceed from right to left on the permutations, and go from left to right inside the cycles.


I realize that in a cycle, say (341) 3 -> 4-> 1-> 3.

Then in this problem of finding "qp" we start with 1, and the right-most permutation. Then from there I am lost. I suppose 1 -> 3 -> ?. after 1 sends to 3 in p, do we then find what 3 would send to in q (except there is no 3 in q)?The answer for this example is (135) but I am completely lost on how to proceed. The book unfortunately isn't very clear on this. Could anybody give me some pointers on how to proceed? Thanks!
 
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welcome to pf!

hi wontonsoup! welcome to pf! :smile:
wontonsoup said:
so qp = (1452) * (341)(25)

… 1 -> 3 -> ?. after 1 sends to 3 in p, do we then find what 3 would send to in q (except there is no 3 in q)?The answer for this example is (135) but I am completely lost on how to proceed.

(135) means that qp sends 1 to 3, qp sends 3 to 5, qp sends 5 to 1

qp sends 1 to 3 because (341) sends 1 to 3, and (1452) leaves 3 alone

qp sends 3 to 5 because (341) sends 3 to 4, and (1452) sends 4 to 5

qp sends 5 to 1 because (25) sends 5 to 2, and (1452) sends 2 to 1 :wink:
 

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