Products formed by mixing Sodium chloride and Potassium iodide?

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SUMMARY

The reaction between Sodium chloride (NaCl) and Potassium iodide (KI) does not yield a traditional net ionic equation. Instead, the products formed are NaI and KCl, resulting in a solution containing four distinct ions: Na+, Cl-, K+, and I-. The professor's guidance emphasizes that this scenario should not be simplified to a net ionic equation, as both products remain in solution.

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I've looked at this website so many times and have been saved by it! Now I need a lil help please! I can finish all the calculations and balance it myself if I can just get the equation!

Homework Statement


Sodium chloride is placed in a solution of Potassium iodide. What products are formed?

Additional notes from the professor say not to treat this as a net ionic equation as two products are formed.


Homework Equations


I know that Sodium chloride is NaCl and Potassium iodide is KI.


The Attempt at a Solution


My guess here is that it would be NaCl + KI → NaI + KCl?
I think that is right but the extra information about it not being a net ionic equation and all has just made me a little unsure! Thank y'all so much for your help!
 
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I have no idea what is the expected answer. There are no two products, there is no reaction at all. The only "product" is a solution containing four different ions.
 

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