# Projectile: Do not understand wording

1. Nov 12, 2007

### Electron17

1. The problem statement, all variables and given/known data

Participants in a road race take water from a refreshment station and throw their empty cups away further down the course. If a runner has a forward speed of 6.20 m/s, how far in advance of a garbage pail should he release his water cup if the horizontal distance between the lid of the garbage can and the runner\'s point of release is 0.50 m?

2. Relevant equations

Rx = Rcos(theta)
Ry = Rsin(thetha)
Kinematics equations

3. The attempt at a solution

I don\'t know what exactly this question is asking for. First of all, what does it mean by \"how far in advance\"? Normally, I would assume that this would mean the horizontal component of distance. However, this is certainly not the case as horizontal distance upon the point of release is given in the question. Unless if this cup is going to magically travel beside him in the x direction after release, it makes no sense whatsoever, especially considering he would merely drop the cup on the ground in reality, 0.50 m short of the garbage can.

By the way, the answer in the back is 2.0 m.

2. Nov 12, 2007

### fliinghier

i'm not sure, but it sounds like the problem means the vertical distance is .5m