A rocket is shot off a 3220 M high mountian at an angle of 35.3 to the horizontal. The rocket lands 9580 m away from the mountian, what was the initial velocity?
y=Vi(y) *t +1/2gt^2
Vi(y)= sin 35.3 Vi
Vi(x)= cos 35.3 Vi
The Attempt at a Solution
I rearanged the top equations to solve for t, then equated them, and replaced subbed the variables so the only var was Vi. When solving for Vi, i got some weird equations i don't know if im using the right equations above, or what.
answers ive gotten: 318.7, 251.74
but neither are correct.
I don't know what to do! :(