The discussion revolves around a projectile motion problem, specifically focusing on determining the maximum height reached by a projectile launched at a speed of 40 m/s at an angle of 60 degrees using conservation of energy principles.
Participants are actively engaging with the problem, raising questions about the components of velocity and the implications of energy conservation. Some have attempted calculations, while others seek clarification on the concepts involved, indicating a productive exploration of the topic.
There is an emphasis on understanding the vertical component of the initial velocity and its significance in calculating maximum height. Participants are also considering the conditions at the highest point of the projectile's trajectory.
wowdusk said:Homework Statement
A projectile is launched with a speed of 40 m/s at an angle of 60 degrees above the horizontal. Use conservation of energy to find the maximum height reached by the projectile during its flight.
Homework Equations
KEi+PEi=KEf+PEfThe Attempt at a Solution
i am not sure where vf would come from. Would it be just Vi*cos(60)?
I am not sure why that makes sense.
Does Vix=Vf?...and why?
wowdusk said:why do i need the vertical component of Vi
I don't know how to find the V at the heighest point...
At the heighest point is the V in vertical direction 0 anyway?