Projectile Motion and the Range Formula

  • Thread starter tharindu
  • Start date
  • #1
4
0
Hey Guys

Im wondering if anyone could help me simplify the range formula for projectile motion. So far ive got R=2v^2 sin(theta) cos(theta)/g.

Help will be appreciated. Thanks
 

Answers and Replies

  • #2
ideasrule
Homework Helper
2,266
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Have you seen the identity sin(2x)=2sinxcosx?
 
  • #3
4
0
No i havent
 
  • #4
ideasrule
Homework Helper
2,266
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Using that identity, you can simplify the range formula easily.

Note that the identity can be derived from sin(a+b)=sin(a)cos(b)+sin(b)cos(a). Set a=b and you get sin(2a)=sin(a)cos(a)+sin(a)cos(a)=2sin(a)cos(a)
 
  • #5
4
0
so then the formula simplifies down to
R= v^2 sin(2x)/g ?
 

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