# Projectile Motion and the Range Formula

Hey Guys

Im wondering if anyone could help me simplify the range formula for projectile motion. So far ive got R=2v^2 sin(theta) cos(theta)/g.

Help will be appreciated. Thanks

ideasrule
Homework Helper
Have you seen the identity sin(2x)=2sinxcosx?

No i havent

ideasrule
Homework Helper
Using that identity, you can simplify the range formula easily.

Note that the identity can be derived from sin(a+b)=sin(a)cos(b)+sin(b)cos(a). Set a=b and you get sin(2a)=sin(a)cos(a)+sin(a)cos(a)=2sin(a)cos(a)

so then the formula simplifies down to
R= v^2 sin(2x)/g ?