- #1

- 4

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Im wondering if anyone could help me simplify the range formula for projectile motion. So far ive got R=2v^2 sin(theta) cos(theta)/g.

Help will be appreciated. Thanks

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- Thread starter tharindu
- Start date

- #1

- 4

- 0

Im wondering if anyone could help me simplify the range formula for projectile motion. So far ive got R=2v^2 sin(theta) cos(theta)/g.

Help will be appreciated. Thanks

- #2

ideasrule

Homework Helper

- 2,266

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Have you seen the identity sin(2x)=2sinxcosx?

- #3

- 4

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No i havent

- #4

ideasrule

Homework Helper

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Note that the identity can be derived from sin(a+b)=sin(a)cos(b)+sin(b)cos(a). Set a=b and you get sin(2a)=sin(a)cos(a)+sin(a)cos(a)=2sin(a)cos(a)

- #5

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so then the formula simplifies down to

R= v^2 sin(2x)/g ?

R= v^2 sin(2x)/g ?

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