Projectile Motion: Angle & Distance of a Baseball Leaving a Bat at 50 m/s

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SUMMARY

The discussion focuses on the projectile motion of a baseball leaving a bat at a velocity of 50 m/s. The ball reaches its apex after 4.42 seconds, prompting questions about the launch angle and the shortest distance to the highest point. To determine the angle of projection, participants suggest using the vertical velocity formula, vy = uy + ay*t, where uy represents the initial vertical velocity and ay is the acceleration due to gravity. The horizontal component of the velocity is essential for calculating the distance to the apex.

PREREQUISITES
  • Understanding of basic physics concepts related to projectile motion
  • Familiarity with kinematic equations, specifically vy = uy + ay*t
  • Knowledge of vector components in motion analysis
  • Basic grasp of acceleration due to gravity (approximately 9.81 m/s²)
NEXT STEPS
  • Calculate the launch angle using the initial vertical velocity and horizontal velocity components
  • Explore the concept of maximum height in projectile motion
  • Learn how to derive horizontal distance traveled in projectile motion
  • Investigate the effects of air resistance on projectile trajectories
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in understanding the dynamics of baseball trajectories.

stevie_char99
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A baseball leaves a bat at a rate of 50 m/s. The ball reaches its highest point after 4.42 seconds.
(a) What is the angle with the horizontal at which the ball leaves the bat?
(b) What is the shortest distance between the starting point and the highest point of the ball?

Attempt:
Vfy = Viy + a [tex]\times[/tex] [tex]\Delta[/tex]t
:confused:
 
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This is a fairly basic projectile motion question, so you might want to brush up the concepts again.
Yes, use vy=uy+ayt
So the question here is what is vy at the topmost point. After you find uy, you can easily find the angle of projection using concepts of vectors.
The second part follows easily once you have the horizontal component of the velocity.
 

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