Projectile Motion: Angle & Distance of a Baseball Leaving a Bat at 50 m/s

[stevie_char99]

A baseball leaves a bat at a rate of 50 m/s. The ball reaches its highest point after 4.42 seconds.
(a) What is the angle with the horizontal at which the ball leaves the bat?
(b) What is the shortest distance between the starting point and the highest point of the ball?

Attempt:
Vfy = Viy + a $$\times$$ $$\Delta$$t

 

[arunbg]

This is a fairly basic projectile motion question, so you might want to brush up the concepts again.
Yes, use v_y=u_y+a_yt
So the question here is what is v_y at the topmost point. After you find u_y, you can easily find the angle of projection using concepts of vectors.
The second part follows easily once you have the horizontal component of the velocity.