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## Homework Statement

A ball thrown horizontally at 22.47 m/s travels a horizontal distance of 43.15 m before hitting the ground. From what height was the ball thrown?

## Homework Equations

Vfy=Viy-g(delta t)

yf=yi+Viy(delta t)-.5g(delta t)^2

yf=yi-(Vfy^2-Viy^2)/2g

## The Attempt at a Solution

Since its thrown horizontally does it arc above the intial position or does it just start its decent so instead of being a upside down "u" shape it just has like a backwards "r" shape?