Projectile Motion Bullet Shot Help

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yogoes123
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Homework Statement

bullet shot horizontally over level ground with a velocity of 300m/s. at the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00m/s

how far does the bullet travel

what is the vertical component of the bullet's velocity at the instant before it his the ground?
I tried a bunch of stuff and I didnt get the right answer, can someone just point me in the right direction? Please, at least tell me which equation to use cause I can't figure this out.
 
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yogoes123 said:
bullet shot horizontally over level ground with a velocity of 300m/s. at the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00m/s
Hi yogoes123. Is there a question attached to this statement?
 
sorry i somehow missed that, very sorry i edited it.
 
yogoes123 said:
I tried a bunch of stuff and I didnt get the right answer, can someone just point me in the right direction? Please, at least tell me which equation to use cause I can't figure this out.
Same here. I can't figure out which equation to use until I have condensed that wordy statement into something that looks more mathematical.

First thing, write down all the information that you know, expressing it as values of variables, e.g.,

bullet: vi = 300 m/sec

casing: vi = ?
    vf = ?

etc.
 
Ok guys i think there is a bit of confusion. The question says the bullet has a horizontal velocity of 300 m/s.

They want you to find range.

They also say the bullet shell falls vertically at a rate of 5 m/s, not sure why but its probably needed.

Thats all they give u.

Horizontal Velocity of bullet: 300 m/s

Vertical velocity of SHELL: 5m/s
 
A sharpshooter shoots a bullet horizontally over level ground with a velocity of 3.00 x 10^2 m/s. At the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00 m/s

a) How far does the bullet travel

b) What is the vertical component of the bullet's velocity at the instant before it hits the ground.
 
yogoes123 said:

Homework Statement




bullet shot horizontally over level ground with a velocity of 300m/s. at the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00m/s. So if you want to find the distance it traveled, you need to find ow far it traveled in x and in y.

how far does the bullet travel

what is the vertical component of the bullet's velocity at the instant before it his the ground?



I tried a bunch of stuff and I didnt get the right answer, can someone just point me in the right direction? Please, at least tell me which equation to use cause I can't figure this out.

Break this down into your knowns and unknowns.

You only have four kinematic equations.

U1L6a1.gif


This problem is a projectile problem that is asking you to break things up in terms of x and y. First the shell moves initially with the bullet at 300 m/s horizontally, and then when it approaches 0 m/s, due to gravity it accelerates vertically at 9.8 m/s2 towards the Earth to reach a final velocity of 5 m/s.

So what do you know?

Horizontal Movement

Vix= 300 m/s
t=(5m/s)/(9.8m/s2)=0.5097s
ax= 0 m/s2
Δx=?

Δx=(vix)(t) + (0.5)(ax)(t)2

Vertical Movement

viy= 0 m/s
vfy= 5m/s
ay= 9.8 m/s2
Δx=?

vfy2 = viy2 + (2)(ay)(Δy)
 
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