Projectile Motion: Calculations for a successful basketball shot

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
7 replies · 2K views
ayderay
Messages
3
Reaction score
0
Homework Statement
A basketball player shoots successfully at goal from a horizontal distance of 5.3m to the centre of the goal ring. She releases the ball at an angle of 48 to the horizontal and 1.2m below the height of the ring. What was the ball’s speed as it left her hand? The answer is 8.1m/s
Relevant Equations
Motion equations
4A14584B-3E5E-44EE-BA13-CE48F2DF1EC9.png
 
Last edited by a moderator:
Physics news on Phys.org
Orodruin said:
Why have you assumed that the ball reaches the maximal height at the midpoint of the trajectory? Can you make an argument for this?
I assumed it..
 
Perhaps a clearer diagram might help. We can ignore the practicalities of the hoop, and just consider the target as a point in space that we want to reach, at the top of the pole:

1587288195354.png


There is another trajectory you could have, I'll let you think of what that might be! It won't affect your calculations.
 
  • Informative
  • Like
Likes   Reactions: berkeman and ayderay
As the ball reaches the ring, how much is its horizontal displacement? How much is its vertical displacement?
 
etotheipi said:
Perhaps a clearer diagram might help. We can ignore the practicalities of the hoop, and just consider the target as a point in space that we want to reach, at the top of the pole:

View attachment 260947

There is another trajectory you could have, I'll let you think of what that might be! It won't affect your calculations.
Ohh, thank u for this, it’s much more understandable. I’ll try the question out again
 
ayderay said:
Ohh, thank u for this, it’s much more understandable. I’ll try the question out again
You treat 1.2m as displacement along vertical.
5.3 m as displacement along horizontal.
And proceed. You will get