Projectile Motion - confirmation on answer(s) needed

[Element1674]

Homework Statement

"A marble rolls off a table with a horizontal velocity of 1.93m/s and onto the floor. The table is 76.5cm above the ground. Air resistance is negligible.
Find the horizontal distance, the air time and the final velocity."

Homework Equations

Δd_y=Vi_yΔt + 0.5a_yΔt²
Rearranged: √(2Δd_y/a_y) = Δt *Equation A*

V_constxΔt=Δd_x *Equation B*

Vf_y² = √(2a_yΔd_y) *Equation C*

The Attempt at a Solution

Use equation A to find Δt, substituting in the variables gives 0.395 seconds. Therefore the ball was in the air 0.395 seconds.

Use equation B to find horizontal distance, substituting in the variables gives 0.762m [F]

Use equation C to find the final vertical velocity, which ends up being 3.87m/s [D]

Now since I know the final vertical velocity (3.87m/s downward) and the final horizontal velocity (1.93m/s [F], it remains constant since there is no air resistance) I can find the final velocity and its angle using pythagorean and trig.

The final velocity is 4.32m/s [63° above the ground] after those calculations. Is that correct? My textbook has 4.3m/s [64° below horizontal] which is oddly worded and doesn't seem to be the same.

 

[mfb]

The textbook just rounded to 1 decimal place, the value looks the same. The velocity is downwards, "below horizontal".