1. The problem statement, all variables and given/known data "A marble rolls off a table with a horizontal velocity of 1.93m/s and onto the floor. The table is 76.5cm above the ground. Air resistance is negligible. Find the horizontal distance, the air time and the final velocity." 2. Relevant equations Δdy=ViyΔt + 0.5ayΔt2 Rearranged: √(2Δdy/ay) = Δt *Equation A* VconstxΔt=Δdx *Equation B* Vfy2 = √(2ayΔdy) *Equation C* 3. The attempt at a solution Use equation A to find Δt, substituting in the variables gives 0.395 seconds. Therefore the ball was in the air 0.395 seconds. Use equation B to find horizontal distance, substituting in the variables gives 0.762m [F] Use equation C to find the final vertical velocity, which ends up being 3.87m/s [D] Now since I know the final vertical velocity (3.87m/s downward) and the final horizontal velocity (1.93m/s [F], it remains constant since there is no air resistance) I can find the final velocity and its angle using pythagorean and trig. The final velocity is 4.32m/s [63° above the ground] after those calculations. Is that correct? My textbook has 4.3m/s [64° below horizontal] which is oddly worded and doesn't seem to be the same.