1. The problem statement, all variables and given/known data At t = 0, a projectile is located at the origin and has a velocity of 20 m/s at 40° above the horizontal. The profile of the ground surface it strikes can be approximated by the equation y = 0.4x – .006x2, where x and y are in meters. Determine: (a) the approximate coordinates of the point where it hits the ground, (b) its velocity and direction when it hits the ground, (c) its highest point in flight and (d) the greatest distance above the ground. See attachment. 2. The attempt at a solution (a) I let y=0 since it will strike the ground at this point on the profile. Then I solved for x: 0 = 0.4x – .006x2 0= x(0.4 – 0.006x) X=0 & x=66.667m So my coordinates for the projectile when it strikes the ground profile will be: (66.67, 0) (b) I used the following: x=66.667 x = xo + (vo)yt t = 4.35 seconds vy = (voy) - at vy = -29.81 m/s vx = (vo)x = 15.32 m/s v = √ (-29.81)2 + (15.32)2 = 33.51 m/s c) I then used the equation: v2 = (vo)y2 + 2(-9.81)h h = 8.43 m d) Assuming that all of the above is correct, I'm not sure how to find this part. I initially thought that it was the same as part c.