The speed of a projectile when it reaches its maximum height is 0.31 times its speed when it is at half its maximum height. What is the initial projection angle of the projectile?
h=(Vi^2 * sin^2 θ) / 2g
R=(Vi^2 * sin2θ) / g
The Attempt at a Solution
I realize that i need to somehow come up with a ratio and set the two equal to each other. However, I'm having difficulty with the initial step. Maybe I could get a hint that could set me on the right track?