Projectile motion: finding angle

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SUMMARY

The discussion focuses on calculating the angle required for a basketball player to successfully make a free throw from a distance of 4.57 m with an initial speed of 7.15 m/s. The player releases the ball from a height of 2.44 m, aiming to hit a basket positioned 3.05 m above the floor. The relevant equations include the horizontal motion equation, x = x_i + v_ix*t, and the vertical motion equation, y = y_i + v_iy*t + a*t^2/2. The equation sin(2theta) = Rxg/iv is suggested for determining the launch angle.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of trigonometric functions, particularly sine and tangent
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of the projectile motion equations
  • Learn how to apply the sine and cosine functions in projectile motion problems
  • Explore the concept of initial velocity components in two-dimensional motion
  • Investigate real-world applications of projectile motion in sports
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Students studying physics, particularly those focusing on mechanics, as well as basketball players and coaches interested in optimizing shooting techniques through understanding projectile motion.

shoust00
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Homework Statement


The free throw line in basketball is 4.57 m (15ft) from the basket, which is 3.05m (10ft) above the floor. A player standing on the free throw line throws the ball with an initial speed of 7.15 m/s, releasing it at a height of 2.44m (8ft) above the floor. At what angle above the horizontal must the ball be thrown to exactly hit the basket?


Homework Equations



I think i will use
sin(2theta)= Rxg/iv

The Attempt at a Solution


I am not sure where to start with this problem

 
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