You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 58.0 m away, making a 3.00 degree angle with the ground.
x(t)= x(0) + VxT
V(Y)= VySin(theta) - 1/2gt^2
The Attempt at a Solution
t= 58/ Vxcos(3)
I know I should then plug this into the y component equation, but I thrown off since there is no height given. I end up with too many variables. I am very lost on this problem!