Projectile motion (hammer throw)

In summary, the conversation involves discussing calculations for the world record for the men's hammer throw event, which involves throwing a hammer as far as possible. The initial velocity is calculated to be 58.31 m/s, and the conversation also covers finding the correct equation to use and addressing misunderstandings about displacement and acceleration in the x-direction.
  • #1
bigsaucy
38
0
Hello all, just a few questions i'd like to clarify. thanks in advance

2.) In the mens hammer throw field event, athletes compete to throw a hammer as far as possible. A Hammer consists of a ball of mass 7.257kg attached to a cable of length 1.215 meters. Atheletes typicall spin the hammer 4 times before releasing. The world record for a hammer throw is 86.74 meters.

a) Assuming that the hammer is thrown at an angle of 45 degrees to the horizontal and neglecting air resistance, calculate the s peed of the ball when released for the world record throw

My solution to part a is as follows:

Vi = Initial velocity
Vf = Final velocity

The ball is launched at an angle of 45 degrees, therefore the y-component of the initial velocity is given by Vi sin (45) = y-component of initial velocity.

Since the y-component has a downward acceleration of -9.8m and it travels 86.74 meters and the final velocity is 0 m/s

then using the equation Vf^2 = Vi^2 + 2ad we get

(0)^2 = (Vi sin 45)^2 + 2(-9.8)(86.74)
1700.104 = (Vi sin 45)^2
Vi sin 45 = 41.2
Vi = 58.31m/s

Is this correct? Thanks.
 
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  • #2
It is not correct. The final velocity is not zero. The final velocity is what it is just before the hammer hits the ground.
 
  • #3
could you point me in the right direction? i have absolutely no idea how to solve it :(
 
  • #5
i've read through the webpage that you linked me.

is it right to assume that the acceleration in the x-direction is 0m/s^2 since we are neglecting air resistance? also; if the acceleration in the x-direction is 0 m/s^2 how on Earth is it possible to find the initial velocity?
 
  • #6
KURUMAN! I think i worked it out! the velocity in the y direction is 0 at the midpoint of the flight therefore if we divide the displacement by 2 and use it in my initial solution i would get the right answer!

IS THAT CORRECT?!
 
  • #7
bigsaucy said:
KURUMAN! I think i worked it out! the velocity in the y direction is 0 at the midpoint of the flight therefore if we divide the displacement by 2 and use it in my initial solution i would get the right answer!

IS THAT CORRECT?!
Some things you said are correct, some are not. It is correct that the velocity in the y direction is zero at the midpoint and that the acceleration in the x direction is zero. However, if you want to use the equation vf2=vi2+2ad, you need to understand that "d" in this equation is the vertical displacement not the given 86.74 meters which is the horizontal displacement.

Suppose you tried something different. Let tf be the time the hammer stays in the air. Can you write two kinematic equations involving tf that give the horizontal position (86.74 m) and the vertical position (0 m) of the hammer at time tf?
 
  • #8
haha i was so sure i was correct before; i used your method and got 20.60 m/s for the initial velocity in the x-direction, can you confirm?
 
  • #9
Incorrect. If you show what you did and exactly how, I might be able to find your mistake.
 

Related to Projectile motion (hammer throw)

1. What is projectile motion?

Projectile motion is the motion of an object through the air or space under the influence of gravity. It is a combination of horizontal and vertical motion, and the object follows a curved path known as a parabola.

2. How does the hammer throw follow projectile motion?

In the hammer throw, the athlete spins before releasing the hammer. This spinning motion creates an initial horizontal velocity, while the force of gravity acts to pull the hammer downwards. As a result, the hammer follows a parabolic path, known as projectile motion.

3. What are the factors that affect the projectile motion in hammer throw?

The factors that affect the projectile motion in hammer throw include the initial velocity, the angle of release, the air resistance, and the force of gravity. These factors determine the shape and distance of the hammer's trajectory.

4. How does air resistance affect the trajectory in hammer throw?

In hammer throw, air resistance acts as a drag force that opposes the motion of the hammer. This force increases as the speed of the hammer increases, and it can cause the hammer to deviate from its expected trajectory.

5. What is the importance of understanding projectile motion in hammer throw?

Understanding projectile motion in hammer throw is crucial for athletes to achieve optimal performance. It allows them to adjust their release angle and velocity to achieve maximum distance and accuracy. It also helps coaches and trainers to analyze and improve an athlete's technique.

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