Projectile Motion Help: Finding Time, Angle, and Velocity

[pberardi]

Homework Statement

Help with projectile motion please?
A particle is at an elevation of 1.02m from the floor when it takes off. It reaches a max height of 1.85m above the floor and stops at .930m above the floor. How do you find the time of flight, the take off angle, the initial vertical and horizontal velocity?

Homework Equations

The Attempt at a Solution

I have no idea how to start this without a given angle. Can someone explain this concept to me?

 

[LowlyPion]

A particle is at an elevation of 1.02m from the floor when it takes off. It reaches a max height of 1.85m above the floor and stops at .930m above the floor. How do you find the time of flight, the take off angle, the initial vertical and horizontal velocity?

I have no idea how to start this without a given angle. Can someone explain this concept to me?

All the info given is vertical. So I don't see any way to address any horizontal or angle of launch issues.

For the time, you can figure that by relating distance gravity and time.

Here are some equations:
https://www.physicsforums.com/showpost.php?p=905663&postcount=2

 

[Delphi51]

No horizontal information is given, so the horizontal velocity could be anything!
The vertical part can be worked out with the usual formulas V = Vi + at and d = di + Vi*t + .5*a*t^2 for accelerated motion. Or even more easily with that formula that has no t in it.