The problem involves projectile motion, specifically finding the initial velocity and maximum height given an angle, horizontal range, and time of flight.
Some participants have offered guidance on using trigonometric relationships to find the initial velocity components. There is an ongoing exploration of the relationships between the horizontal and vertical components of motion, but no consensus has been reached on the complete solution.
Participants express uncertainty about which equations to apply and the implications of horizontal motion in the context of projectile motion.
loopsnhoops said:Homework Statement
Find the initial velocity and the maximum height
θ = 28˚
horizontal range/distance/s = 68 m
time = 6.30 s
Homework Equations
suvat equations not so sure which one though
The Attempt at a Solution
I think to find the initial velocity I use the equation:
s=ut+(1/2)at^2
I think acceleration horizontally is 0 so:
u(h) = s(h)/t
Use the last equation, u(h) = s(h)/t to find the horizontal component of the velocity. Since the horizontal component of the velocity is constant, what does this tell you about the horizontal component of the initial velocity?loopsnhoops said:Homework Statement
Find the initial velocity and the maximum height
θ = 28˚
horizontal range/distance/s = 68 m
time = 6.30 s
Homework Equations
suvat equations not so sure which one though
The Attempt at a Solution
I think to find the initial velocity I use the equation:
s=ut+(1/2)at^2
I think acceleration horizontally is 0 so:
u(h) = s(h)/t
Yes. The horizontal component of the velocity doesn't change, so that is the same as the horizontal component of the initial velocity.loopsnhoops said:It is the same as the u(h)?