Ok, so, I've about had it rattling my brain on this. I'm stumped.
Protons are projected with an initial speed vi = 9.89x10^3 m/s into a region where a uniform electric field E = (-720 j) N/C is present. The protons are to hit a target that lies at a horizontal distance of 1.27 mm from the point where the protons cross the plane and enter the electric field.
Find the two projection angles that result in a hit and the corresponding times of flight.
The only thing I was able to compute (hopefully I got it right) was that the acceleration in the y-direction (as there is none in the x) is -6.89687x10^10 m/s^s. Since E is -720j and knowing the charge and mass of a proton I calculated that... but that's about all I've got.
I know all of my kinematic equations but I'm still at a loss on this problem...
The Attempt at a Solution