Projectile Motion Jumping Man Problem

[dj0320]

Homework Statement

In a scene in an action movie, a stunt man jumps from the top of one building to the top of another building 4.4 m away. After a running start, he leaps at an angle of 15◦ with respect to the flat roof while traveling at a speed of 5.0 m/s. The acceleration of gravity is 9.81 m/s^2. To determine if he will make it to the other roof, which is 2.2 m shorter than the building from which he jumps, find his vertical displacement upon reaching the front edge of the lower building with respect to the taller building. Answer in units of m.

Homework Equations

vx = vi cos theta
viy = vi sin theta
delta x = vx*delta t
delta y = vix*delta t + (1/2)g(delta t)^2
I'm not sure which ones to use.

The Attempt at a Solution

vix = vi cos theta = 5 cos 15 = 4.8296
delta x = 4.4 (given)
4.4/4.8296 = time = .911

Then I'm stuck here.

 

[Spinnor]

Take the time you found, .911 seconds and plug it into your equation for vertical distance and see where the stunt guy is?