Projectile Motion of a Man Problem

In summary, a man throws a rock from the roof of a 14.1m building with a velocity of 29.3m/s at an angle of 29.9 degrees above the horizontal. Ignoring air resistance, the maximum height reached by the rock is 10.9m and the velocity just before it strikes the ground is 33.7m/s. The horizontal distance from the base of the building to the point where the rock strikes the ground is 57.4m, taking into consideration the total flight time of 3.75 seconds.
  • #1
TheRedDevil18
408
1

Homework Statement



A man stands on the roof of a building of height 14.1m and throws a rock with a velocity of magnitude 29.3m/s at an angle of 29.9 degrees above the horizontal. You can ignore air resistance.

1) Calculate the maximum height above the roof reached by the rock.

2) Calculate the magnitude of the velocity of the rock just before it strikes the ground.

3) Calculate the horizontal distance from the base of the building to the point where the rock strikes the ground.

Homework Equations





The Attempt at a Solution



1) 10.9 m, I know that's right

2) 33.7 m/s, that's also correct

3) 57.4 m, but this answer is wrong, I think

this is how I worked it out
x = Vx*t
= 25.4*2.26 (The vertical time it took to drop from it's max height to the ground)
= 57.4 m
 
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  • #2
TheRedDevil18 said:
this is how I worked it out
x = Vx*t
= 25.4*2.26 (The vertical time it took to drop from it's max height to the ground)
= 57.4 m
What about the time it took to rise to the maximum height?
 
  • #3
Doc Al said:
What about the time it took to rise to the maximum height?

Ok so the time it took to rise to max height was 1.49's so the total flight time will be 2.26+1.49 = 3.75's

So it should be,

x = Vx*t
= 25.4*3.75
= 95.25 m, Correct ?
 
  • #4
TheRedDevil18 said:
Ok so the time it took to rise to max height was 1.49's so the total flight time will be 2.26+1.49 = 3.75's

So it should be,

x = Vx*t
= 25.4*3.75
= 95.25 m, Correct ?
Good.
 
  • #5
Doc Al said:
Good.

Thanks ! :)
 

FAQ: Projectile Motion of a Man Problem

1. What is projectile motion?

Projectile motion is the curved path an object takes when it is thrown or launched into the air. It is affected by both the object's initial velocity and the force of gravity.

2. How does projectile motion apply to a man problem?

In a "man problem," a person is thrown or launched into the air, and their motion can be described by the principles of projectile motion. This can be used to calculate the person's trajectory, height, and distance traveled.

3. What are the key variables in a projectile motion of a man problem?

The key variables in a projectile motion problem are the initial velocity, the angle of launch, and the force of gravity. These variables can be used to determine the final position and velocity of the person.

4. How is the angle of launch important in a man problem?

The angle of launch determines the shape of the person's trajectory. A higher angle will result in a higher peak height and shorter distance traveled, while a lower angle will result in a lower peak height and longer distance traveled.

5. How does air resistance affect projectile motion in a man problem?

Air resistance can affect the trajectory of a person in a projectile motion problem, making it slightly different from the theoretical calculations. This is because air resistance acts as a force that opposes the person's motion, causing them to slow down and potentially change direction.

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