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Projectile Motion Kinematics: A catapult launches a rock....
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[QUOTE="DracoMalfoy, post: 6052999, member: 650272"] [h2]Homework Statement [/h2] A catapult launches a rock with an initial velocity of 50m/s at 35 degrees above the horizontal. The rock must clear 3.5m at 10m away in order to make it over a castle wall to get to the enemy. Do the knights succeed? By how much do they clear the wall or miss clearing the wall? (Ans: 3.1m) [h2]Homework Equations[/h2] [U]X-direction[/U][/B] [LIST] [*]Vfx=Vix: Vicosθ [*]a= 0m/s [*]Δx=Vix(t) [/LIST] [B][U]Y-direction[/U][/B] [LIST] [*]Viy=Visinθ [*]Vfy-Visinθ+gt [*]Δy=(visinθ)(t)+1/2gt^2 [*]Vfy^2=(Visinθ)^2+2gΔy [*]Δy=1/2(Vfy+Visinθ)(t) [*]a=-9.8m/s^2 [/LIST][h2]The Attempt at a Solution[/h2] I drew a picture. TheViy is 28.6. The Vix and Vfx is 40.9. The acceleration in the x-direction is zero. In the y-direction its -9.8m/s^2. Am I supposed to the Δy and then subtract it from 3.5 which is the height of the castle at 10m away? [/QUOTE]
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Projectile Motion Kinematics: A catapult launches a rock....
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