Projectile Motion Long Jump Help

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SUMMARY

The discussion focuses on solving a projectile motion problem related to long jump performance. The athlete takes off at a 30-degree angle and travels 7.80 meters. To determine the takeoff speed, the equations of motion are applied, specifically using the range formula R = (u²sin(2θ))/g. The user struggles with calculating the initial velocity and time of flight, indicating a need for clarity in applying projectile motion principles.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of trigonometric functions in physics
  • Basic grasp of gravitational acceleration (g = 9.81 m/s²)
NEXT STEPS
  • Calculate the initial velocity using the formula R = (u²sin(2θ))/g
  • Explore the effects of varying launch angles on projectile distance
  • Learn how to derive time of flight using t = 2usin(θ)/g
  • Investigate the impact of increasing takeoff speed on jump distance
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as athletes and coaches interested in optimizing long jump performance.

singlish
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An athlete executing a long jump leaves the ground at a 30 degree angle and travels 7.80m.
(a). What was the takeoff speed?
(b). If this speed were increased by just 5.0 percent, how much longer would the jump be?

I'm having some troubles with part a. I've been struggling to comprehend projectile motion and I've been trying to find T using different methods but none of them work. I eventually came up with 9s using cosine, but I can't find initial velocity now. Any advice or tips would be appreciated.
 
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x=(ucos30)t
t=2usin30/g
R=(u^2sin(2*30))/g
 
guys.. can you please help me with this simple problem my instructors gave us for home work... its about projectile motion..

what is the time if the displacement is at 21 meters having a 35degrees angle with the original velocity of 100m/s.
 

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