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## Homework Statement

An Olympic long jumper is capable of jumping 7.7m. Assuming his horizontal speed is 8.8m/s as he leaves the ground, how long is he in the air? Assume that he lands standing upright--that is, the same way he left the ground.

## Homework Equations

Y = xtan(theta)

_{0}- ((g)/2V

_{0}

^{2}cos

^{2}(theta)

_{0})X

^{2}

V

_{x}

_{0}= V

_{0}cos(theta)t

And other that I attempted at using...

## The Attempt at a Solution

Ok so I have tried several things but, I dont have the angle at which he jumps to figure out the time, and you only get the initial velocity for the horizontal direction. I was gonna use

V

_{x}

_{0}= V

_{0}cos(theta)t

to solve for Cos(theta) and figure out my angle but I dont even Have V, only V

_{x}so am I suposed to assume they are the same?

If someone can point me in the right direction, this is the only problem I couldn't figure out earlier today.