1. The problem statement, all variables and given/known data An Olympic long jumper is capable of jumping 7.7m. Assuming his horizontal speed is 8.8m/s as he leaves the ground, how long is he in the air? Assume that he lands standing upright--that is, the same way he left the ground. 2. Relevant equations Y = xtan(theta)0 - ((g)/2V02cos2(theta)0)X2 Vx0 = V0cos(theta)t And other that I attempted at using... 3. The attempt at a solution Ok so I have tried several things but, I dont have the angle at which he jumps to figure out the time, and you only get the initial velocity for the horizontal direction. I was gonna use Vx0 = V0cos(theta)t to solve for Cos(theta) and figure out my angle but I dont even Have V, only Vx so am I suposed to assume they are the same? If someone can point me in the right direction, this is the only problem I couldn't figure out earlier today.