Projectile Motion - need help

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To determine the time required for a projectile to cross a line at an angle beta, the projectile's motion is described by the equation y = y0 + v0(sin alpha)t - 4.9t^2. The line can be represented as y = ax, where "a" is derived from the angle beta. By finding y in terms of beta and equating it to the projectile's motion equation, the intersection point can be calculated. This intersection point provides the value of x, which can then be used to solve for time t. The discussion emphasizes the need to combine the equations of motion and the line to find the solution effectively.
don_anon25
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Projectile Motion -- need urgent help :)

If a projectile is fired from the origin of the coordinate system with an initial velocity v and in a direction making an angle alpha with the horizontal, calculate the time required for the projectile to cross a line passing thorugh the origin and making an angle beta less than alpha with the horizontal.

I know that the position of the projectile is described by
y=y0+v0(sin alpha)*t-4.9t^2.

I let the line be y=ax. I also drew a triangle with Beta as the angle, y=ax as the opposite side, and x as the adjacent side. I'm assuming I want to find y in terms of Beta and then set this equal to y in my projectile motion equation...then solve for t?

Thanks in advance!
 
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don_anon25 said:
I know that the position of the projectile is described by
y=y0+v0(sin alpha)*t-4.9t^2.
Combine this with the equation for the horizontal position and you can get y as a function of x.

I let the line be y=ax. I also drew a triangle with Beta as the angle, y=ax as the opposite side, and x as the adjacent side. I'm assuming I want to find y in terms of Beta and then set this equal to y in my projectile motion equation...then solve for t?
Write the equation of the straight line. (What is "a" in terms of beta?)

Now you can find the value of x where the two functions intersect. And then plug that into one of the other equations to solve for the time.
 
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