The kicker on a football team can give the ball an initial speed of 26.2 m/s. If he is to score a field goal from a point 42.2 m in front of goalposts whose horizontal bar is 3.75 m above the ground, what is the minimum and maximum angle above the horizontal he must kick the ball? I figured out this much ax=0 ay= -9.8 vx= sin(theta)*26.2 vy= cos(theta)*26.2 x= sin(theta)*26.2x y= cos(theta)*26.2x-4.9x^2 and I think 3.75= cos(theta)*26.2x-4.9x^2 My first attempt at an answer yielded 5.06 and 26.something. I tried using arctan(3.75/42.2) to get an angle. I'm not really sure how to approach this problem since theta is missing.