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The kicker on a football team can give the ball an initial speed of 26.2 m/s. If he is to score a field goal from a point 42.2 m in front of goalposts whose horizontal bar is 3.75 m above the ground, what is the minimum and maximum angle above the horizontal he must kick the ball?

I figured out this much

ax=0

ay= -9.8

vx= sin(theta)*26.2

vy= cos(theta)*26.2

x= sin(theta)*26.2x

y= cos(theta)*26.2x-4.9x^2

and I think

3.75= cos(theta)*26.2x-4.9x^2

My first attempt at an answer yielded 5.06 and 26.something. I tried using arctan(3.75/42.2) to get an angle. I'm not really sure how to approach this problem since theta is missing.

I figured out this much

ax=0

ay= -9.8

vx= sin(theta)*26.2

vy= cos(theta)*26.2

x= sin(theta)*26.2x

y= cos(theta)*26.2x-4.9x^2

and I think

3.75= cos(theta)*26.2x-4.9x^2

My first attempt at an answer yielded 5.06 and 26.something. I tried using arctan(3.75/42.2) to get an angle. I'm not really sure how to approach this problem since theta is missing.

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