Projectile motion of a kicked ball

  • Thread starter fiziks09
  • Start date
  • #1
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Homework Statement


A ball is kicked in the air with an initial velocity of 15m/s at an angle of 37 degrees; 0.8 m above the ground. How long is the ball in the air????


Homework Equations





The Attempt at a Solution


I resolved the vector into its components and the y component was 9.02
I calculated time to reach maximun height using t = 9.02/9.8 = 0.92

and then the whole time of flight was = 2*0.92 = 1.8s.

please is this correct?? did i do the right thing here?? thanks
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
8
It is not correct. The ball is kicked from 0.8 m above the ground. And it is required to find the time to reach the ground.

Use the formula

[tex]-y = v_yt -
\frac{1}{2}gt^2[/tex]

Solve the quadratic to find t.
 
Last edited:
  • #3
754
1
I resolved the vector into its components and the y component was 9.02
I calculated time to reach maximun height using t = 9.02/9.8 = 0.92

and then the whole time of flight was = 2*0.92 = 1.8s.

please is this correct?? did i do the right thing here?? thanks

Don't forget that the ball was kicked from 0.8m above the ground...
 

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