# Projectile motion of a kicked ball

## Homework Statement

A ball is kicked in the air with an initial velocity of 15m/s at an angle of 37 degrees; 0.8 m above the ground. How long is the ball in the air????

## The Attempt at a Solution

I resolved the vector into its components and the y component was 9.02
I calculated time to reach maximun height using t = 9.02/9.8 = 0.92

and then the whole time of flight was = 2*0.92 = 1.8s.

please is this correct?? did i do the right thing here?? thanks

## Answers and Replies

rl.bhat
Homework Helper
It is not correct. The ball is kicked from 0.8 m above the ground. And it is required to find the time to reach the ground.

Use the formula

$$-y = v_yt - \frac{1}{2}gt^2$$

Solve the quadratic to find t.

Last edited:
I resolved the vector into its components and the y component was 9.02
I calculated time to reach maximun height using t = 9.02/9.8 = 0.92

and then the whole time of flight was = 2*0.92 = 1.8s.

please is this correct?? did i do the right thing here?? thanks

Don't forget that the ball was kicked from 0.8m above the ground...