A broad jumper begins his jump at an angle of 22 degrees from the horizontal. At the middle of the jump he reaches a height of 70.0cm
a. What is his horizontal velocity
b. What is his horizontal displacement
The Attempt at a Solution
Sin 22 = x/70 x= 26.2
Since it's half way up, you'd have to double the time to find the entire time(?) needed for the entire horizontal displacement, but I have no clue what to do after getting time (if that's even right).