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SigFig
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Homework Statement
A broad jumper begins his jump at an angle of 22 degrees from the horizontal. At the middle of the jump he reaches a height of 70.0cm
a. What is his horizontal velocity
b. What is his horizontal displacement
ANSWER: 9.16m/s
Homework Equations
dh=vht
dv=1/2at^2
t=vv/a
The Attempt at a Solution
Sin 22 = x/70 x= 26.2
26.2=1/2(9.8)t^2
√t
t= 2.3sec
Since it's half way up, you'd have to double the time to find the entire time(?) needed for the entire horizontal displacement, but I have no clue what to do after getting time (if that's even right).