1. The problem statement, all variables and given/known data A broad jumper begins his jump at an angle of 22 degrees from the horizontal. At the middle of the jump he reaches a height of 70.0cm a. What is his horizontal velocity b. What is his horizontal displacement ANSWER: 9.16m/s 2. Relevant equations dh=vht dv=1/2at^2 t=vv/a 3. The attempt at a solution Sin 22 = x/70 x= 26.2 26.2=1/2(9.8)t^2 √t t= 2.3sec Since it's half way up, you'd have to double the time to find the entire time(?) needed for the entire horizontal displacement, but I have no clue what to do after getting time (if that's even right).