1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Projectile Motion of ice skater

  1. Oct 15, 2007 #1
    1. The problem statement, all variables and given/known data

    You are planning a stunt to be used in an ice skating show. For this stunt a skater will skate down a frictionless ice ramp that is inclined at an angle of 15° above the horizontal. At the bottom of the ramp, there is a short horizontal section that ends in an abrupt drop off. The skater is supposed to start from rest somewhere on the ramp, then skate off the horizontal section and fly through the air a horizontal distance of 6.40 m while falling vertically for 3.80 m, before landing smoothly on the ice. How far up the ramp should the skater start this stunt?

    2. Relevant equations

    3. The attempt at a solution

    I found, using the Pythagorean theorem, that the distance diagonally (the hypotenuse) is 7.44m, but I am kind of stuck there.

    Thanks a lot for you help!
  2. jcsd
  3. Oct 15, 2007 #2
    Start by finding how long it takes for an object to fall 3.8m vertically using gravitational accel. Then use that time to relate how fast she must be going to travel 6.4m in the time that you find. That is a start
  4. Oct 15, 2007 #3
    so, using d= vt + (5.)(a)(t*t) <---- that's t squared, sorry :)

    i did 3.8 = (0)(t) + (.5)(9.8)(t*t)

    and found t to be be .88s

    then i did

    6.4 = v(.88) + (.5)(9.8)(.88)

    and got v to be 2.97m/s

    so that means that the skater will have to be going 2.97m/s. it this correct so far?
  5. Oct 15, 2007 #4
    the "short horizontal section" in the problem implies that there will be no acceleration in the horizontal direction. So your second formula is wrong
  6. Oct 15, 2007 #5
    so it would just be d = vt

    6.4 = v(.88)

    = 7.27 m/s ?

  7. Oct 15, 2007 #6
    can someone explain where to go from here? thanks
  8. Oct 15, 2007 #7
    Try using energy analysis (PE and KE) to find how far up she needs to be to achieve that speed...
  9. Oct 15, 2007 #8
    im sorry, i dont think we have covered that yet in class. i tried to look it up online, but im not really having any luck. is there any other way to solve?
  10. Oct 15, 2007 #9
    Use force analysis to find how fast an object accelerates down a ramp that is 15 degrees. after that just use normal kinematic equations to relate distance/velocity/acceleration
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Projectile Motion of ice skater
  1. Ice skater gliding (Replies: 41)