What Is the Skater's Acceleration on the Rough Ice?

[Ashkon]

Homework Statement

A skater moving on a frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadly, the continues at 6.0 m/s. What is her acceleration on the rough Ice

Homework Equations

v² = v_o ² + 2a (d-d_o)

The Attempt at a Solution

I have tried to set up the formula but I'm not sure how to do it properly.

a = v_o ² + 2v² (d-d_o)

 

[andrewkirk]

v and v₀ are the final and initial velocities.
d and d₀ are the distances from the skater's starting point to the end and beginning of the rough ice

 

[SteamKing]

Homework Statement

A skater moving on a frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadly, the continues at 6.0 m/s. What is her acceleration on the rough Ice

Homework Equations

v² = v_o ² + 2a (d-d_o)

The Attempt at a Solution

I have tried to set up the formula but I'm not sure how to do it properly.

a = v_o ² + 2v² (d-d_o)

Your algebra in transposing the Equation in 2.) to the Equation in 3 is a little dodgy.

You can't just switch the positions of a and v² like you show.

 

[Ashkon]

v and v₀ are the final and initial velocities.
d and d₀ are the distances from the skater's starting point to the end and beginning of the rough ice

I understand that, I just have problems with setting up the formula.

 

[SteamKing]

I understand that, I just have problems with setting up the formula.

Well, we can't do your algebra for you. You'll have to take the Equation in Section 2 and solve for a using standard algebraic rules.

 

[Ashkon]

Deleted

 

[SteamKing]

I'm not very good at transposing. I think that moving the v² will make it a fraction an it would be on the bottom? Or will it just stay the same but v² goes in another place?

Do you or do you not understand algebra?

You've already tried switching a and v², and we told you that wasn't correct.