Projectile Motion - one question.

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Homework Help Overview

The problem involves projectile motion, specifically calculating the necessary horizontal speed for a circus performer to land in a net positioned 5 meters away while falling from a height of 10 meters.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the time it takes for the performer to fall 10 meters and how that relates to horizontal distance traveled. Some suggest using gravitational acceleration in calculations, while others express uncertainty about the relevant equations.

Discussion Status

Several participants have offered guidance on calculating the time of fall and the necessary horizontal speed. There is a mix of attempts to derive equations and expressions of uncertainty about the correct approach. No consensus has been reached, but productive lines of reasoning are being explored.

Contextual Notes

Some participants indicate a lack of familiarity with the relevant equations and concepts, which may affect the depth of the discussion.

MoreZitiPlease
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Homework Statement



A circus performer wants to land in a net of 5m to the right of where she willlt go of the trapeze. IF she is 10m above the net, how fast must she be moving horizontally when she let's it go?

Homework Equations


I know we are trying to solve for speed and we are giving distance

The Attempt at a Solution



No idea
 
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two-step process:
how long does it take for her to fall 10m?
how far can she travel in that time horizontally (given a certain initial speed)?
 
id guess use 9.8
 
write down the relevant equations, and you are good to go
 
i don't know them

whatr re thy
 
First you must calculate the time it takes for her to travel the 10m down vertically.
Once you know that time, that is also the time that she has to travel 5m horizontally.
So you can calculate her horizontal speed necessary by dividing the distance (5m) by the time.
 
t = (2y/g) where y = distance
so, t= ((2)(10)/-9.8) ~= 2.04 s
5/2.04 = your answer.

I could be wrong =)...hopefully not!
 
i'll see
 

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