1. The problem statement, all variables and given/known data A student in the back row of class fires a pea shooter in an attempt to hit the blackboard. The student fires it a distance of 23m from his seat to hit the black board. The pea hits the board after 1.4 seconds at a location 9.3 meters below the ceiling. The pea is fired from a vertical position, 3.1m below the ceiling. Find the maximum height of the pea in its trajectory 2. Relevant equations u = initial velocity x = ut y = ut + 1/2at2 v = u + at v2 = u2 + 2ad 3. The attempt at a solution Firstly, attempting to find initial velocity for y direction: y direction: d = 9.3 - 3.1 = 6.2 m u = vsintheta a = - 9.8 m/s2 t = 1.4 s Using equations of motion: 6.2 = vsintheta + 1/2(-9.8)(1.4)2 vsintheta = 15.08 m/s Finding max distance: u = 15.08 m/s v = 0 m/s a = - 9.8 m/s 0 = 15.082 + 2(-9.8)(d) d = 12.74 m I feel like I've done something wrong? Not entirely sure, though. Don't have the answer to the questions. Thanks for the help!